kctf2026 - Challenge 7 - Hidden Energy Undercurrent
SkillWeb & browsingLets your agent reverse engineer a deterministic encryption scheme from known plaintext examples.
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Details
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About this skill
KCTF 2026 Challenge 7 HexMaze deterministic encryption reverse engineering: fixed 6-byte skeleton, nibble-cyclic transformation, and 3-byte chunk position rearrangement; recovers the full algorithm via known plaintext.
What this skill tells your AI
The instructions your AI receives, as published by manyuegong33/r0crawl_skills in skills/kctf2026-题7-暗能潜流/SKILL.md and read by ahel’s review.
目标为确定性加密程序 HexMaze。明文按 ASCII 字节处理,算法包含字节编码、十六进制位运算、模 16 循环偏移、固定位置重排和固定摘要扰动。所有样例和 FLAG 均使用密钥 121。
可验证常量
- 密钥:
121 - 已知样例:
TLU→94AA48550495Hello→34BB405504B5223594B94C532026→A48844556485223322356483abcd!→547B475584B5223564BB4553
- FLAG 密文:
14CC4655547594BC475584C5848A43551495448C445584C5D4C9475564C534A84B55A4B574BA4355F495A48844556485648C495534A5548C4F5584A5B4BB405554B522332235A4B3 - 最终 FLAG:
flag{T1u_2026_Kc7f_Crypt0_M4ster!}
标准解法流程
-
观察密文结构
- 密文按 6 字节一组输出
- 3 字节明文对应 1 个 6-byte 块
- 不足 3 字节的尾部仍补成完整 6 字节输出块
- 完整块结构:
[a,4] [b,c] [4,d] [5,5] [e,4] [f,5],有效数据半字节为a b c d e f
-
确定 FLAG 长度
- FLAG 密文 144 hex chars = 72 bytes = 12 blocks
- 最后一块结构
22 33 22 35 ?4 ?3与余 1 字节尾块一致 - 因此
len(flag) mod 3 = 1,总长度11 * 3 + 1 = 34字节
-
提取有效数据
- 从每个 6-byte 块中提取有效半字节:
byte0.high, byte1.high, byte1.low, byte2.low, byte4.high, byte5.high - 尾块根据
len(plaintext) mod 3提取不同位置
- 从每个 6-byte 块中提取有效半字节:
-
恢复密钥变换
- 密钥
121表示周期操作:1, 2, 1, 1, 2, 1, ... - key=1:
(H,L) -> (L+4, H+5) mod 16(交换 + 偏移) - key=2:
(H,L) -> (H+5, L+4) mod 16(不交换 + 偏移) - 逆变换:key=1 时
L=(a-4)%16, H=(b-5)%16;key=2 时H=(a-5)%16, L=(b-4)%16
- 密钥
-
恢复位置重排
- 加密时从字符串右侧每 3 字节分块
- 完整块:
ABC -> CAB(右循环 1 位) - 两字节块:
AB -> BA - 单字节:
A -> A - 块顺序从右向左输出
- 解密时执行左循环 1 位并反转块顺序
-
解密 FLAG
- 按固定骨架提取有效半字节
- 按密钥周期执行逆半字节变换
- 逆位置重排得到最终 FLAG
可复用检查清单
- 观察密文固定块结构和固定半字节模式
- 通过已知明文恢复密钥对应的周期变换
- 识别分块位置重排模式(右循环、块反转)
- 处理尾块特殊情况(与长度模 3 相关)
- 逐层逆向:骨架提取 → 密钥逆变换 → 位置逆重排
通用方法论(重点)
本题只是"自定义分块编码/加密"的一个实例。遇到同类型新题不要抄本题常量, 照
METHODLOGY.md的五步推导法 +derive_solver.py自动推导器,喂几组已知样例即可重新推出全部参数(块结构/密钥周期/重排/尾块位置)。 方法论文档含:题型识别特征、五步推导法、验证清单、常见坑对照表。
Signals
- GitHub stars
- 294
- Forks
- 103
- Last commit
- Sep 2026
Advanced
- Item type
- skill
- Key
kctf2026-7- Source
- github.com/manyuegong33/r0crawl_skills
github.com/manyuegong33/r0crawl_skills
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